Enviromental Assignment Example | Topics and Well Written Essays - 500 words

Enviromental - Assignment Example Mass of Ozone in troposphere = 2.28ãâ€"1013g. Correspondingly, it implies 3 ppm = 3 volumes of Ozone gas/106 volumes of air. Ppmv of Ozone in stratosphere = (ppm/MW) Ãâ€"22.4. In this manner, ppmv = (3/48) Ãâ€"22.4 = 1.4ppmv. This implies 1 million volumes of air have 1.4 volumes of Ozone by mass. 1 million volumes of air in stratosphere speak to 2.5ãâ€"1020 g of air. Shouldn't something be said about 1.4 ppmv of Ozone? Mass of Ozone = (1.4ãâ€"2.5ãâ€"1020)/1ãâ€"106. Mass of Ozone = 3.5ãâ€"1014g. Fractional weight, Px = Cxãâ€"P where Px is halfway weight, Cx is the incomplete centralization of gas x and P is the whole weight. N2O, MW of 44, has a grouping of 0.31ppm at ground level. Ne, MW of 20, has grouping of 18 ppm at 30km. Weight of Ne concerning the height of 30 km is given by Pa = 0.9877a, where a = elevation in 100’s of meters. Consequently, Pa = 0.9877300= 0.0244atm. Incomplete weight of Ne = 18ppmãâ€"0.0244 = 0.44 atm. Fractional weight of N2O = 0.31ãâ€"1 = 0.31 atm. Consequently, Ne has a more noteworthy halfway weight that N2O. 100% relative moistness speaks to 0.031atm H2O. Then again, fluid water is available at 100ug/m3. Expecting a temperature of 25oC, at that point we will change over ug/m3 into ppmv utilizing the recipe ppmv = (mg/m3 Ãâ€"oK)/(0.08205 Ãâ€"MW). Concerning water fume, ppmv = (0.1 mg/m3 Ãâ€"298)/(0.08205 Ãâ€"18). Ppmv = 20.18. Utilizing PV = nRT, at that point moles of air in 1 mol of vaporous blend = 1ãâ€"106/6.023ãâ€"1023 = 1.66ãâ€"10-18. Changing over moles into volume we get 4.06ãâ€"10-14 cm3. Accordingly, the urban environment contains 20.18 atoms of fluid H2O/4.06ãâ€"10-14 cm3 of air. On water fume, 30% relative moistness speaks to (30 Ãâ€"0.031)/100 = 0.0093 atm. In 1 atm, volume of gas = 24.45L, in 0.0093 atm, volume of fume = (0.0093 Ãâ€"24.45)/1 = 0.227L. In light of hypothesis, 1 mol = 24.45L (Dr Richards 01). In this way, 0.227L contains (0.227ãâ€"1)/24.45 = 0.0093 atoms/L. As far as cm3, the climate has 9.3